(5x-1)(x-2)=4x^2-8

Solution for (5x-1)(x-2)=4x^2-8 equation:

(5x-1)(x-2)=4x^2-8

We move all terms to the left:

(5x-1)(x-2)-(4x^2-8)=0

We get rid of parentheses

-4x^2+(5x-1)(x-2)+8=0

We multiply parentheses ..

-4x^2+(+5x^2-10x-1x+2)+8=0

We get rid of parentheses

-4x^2+5x^2-10x-1x+2+8=0

We add all the numbers together, and all the variables

x^2-11x+10=0

a = 1; b = -11; c = +10;
Δ = b2-4ac
Δ = -112-4·1·10
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-9}{2*1}=\frac{2}{2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+9}{2*1}=\frac{20}{2}
=10
$